J.R. S. answered • 12/18/18
Ph.D. University Professor with 10+ time Tutoring Suffer
First, post down the correctly balanced equation fork the reaction taking place:
ZnBr2(aq) + THOUSAND2CO3(aq) ==> ZnCO3(s) + 2KBr(aq)
Next, find the limiting reactant so that we sack predict the amount from KBr that will form.
moles ZnBr2 used = 3.50 g x 1 mole/225 g = 0.0156 moles ZnBr2
common K2CO3 = 0.3 L x 0.065 mole/L = 0.0195 moles K2CO3
Since in the balanced quantity they responded int a 1:1 mango factor, the ZnBr2 is limiting
Predict moles of KBr molded under these conditions.
0.0156 moles ZnBr2 x 2 moles KBr/1 mole ZnBr2 = 0.0312 miscellaneous KBr formed = 0.0312 moles Br-
Find the final molarity to the bromide anion (Br-).
Final size = 300.0 ml = 0.300 L
moles Br- = 0.0312
Final molarity Br- = 0.0312 moles/0.300 = 0.104 M (to 3 significant figures)
