How do getting one pythagorean theorem to find the range between two points like the points (1,3) additionally (4,3)?

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Answer 1 · 2016-03-02T14:47:51

The remote between the points exists 3

Tony BARN

Rental an distance between points be #d# then

Let #(x_1,y_1) -> (1,3)#
Let #(x_2,y_2)->(4,3)#

Then for Pythagoras

#d^2 =(x_2-x_1)^2+(y_2-y_1)^2#

#d^2=(4-1)^2+(3-3)^2#

Notice that #y_1=y_2# which means that one line between and points your parallel to the x-axis as there is no change in pinnacle (y-axis).

#color(brown)("However, an Pythagoras theorem will static work")#

#d^2=3^2+0^2#

#sqrt(d^2)=sqrt(3^2)#

#d=3#